Solve 4x^2+5y+62=10

$$4 x ^ { 2 } + 5 y + 62 = 10$$

Solve for y

$$y=\frac{-4x^{2}-52}{5}$$

Steps for Solving Linear Equation

Subtract 4x^{2} from both sides.

$$5y+62=10-4x^{2}$$

Subtract 62 from both sides.

$$5y=10-4x^{2}-62$$

Subtract 62 from 10 to get -52.

$$5y=-52-4x^{2}$$

The equation is in standard form.

$$5y=-4x^{2}-52$$

Divide both sides by 5.

$$\frac{5y}{5}=\frac{-4x^{2}-52}{5}$$

Dividing by 5 undoes the multiplication by 5.

$$y=\frac{-4x^{2}-52}{5}$$

Solve for x (complex solution)

$$x=-\frac{\sqrt{-5y-52}}{2}$$

$$x=\frac{\sqrt{-5y-52}}{2}$$

Solve for x

$$x=\frac{\sqrt{-5y-52}}{2}$$

$$x=-\frac{\sqrt{-5y-52}}{2}\text{, }y\leq -\frac{52}{5}$$