Solve 4x+37-6(x-1)leq3

$$4 x + 37 - 6 ( x - 1 ) \leq 3$$

Solve for x

$$x\geq 20$$

Solution Steps

Use the distributive property to multiply -6 by x-1.

$$4x+37-6x+6\leq 3$$

Combine 4x and -6x to get -2x.

$$-2x+37+6\leq 3$$

Add 37 and 6 to get 43.

$$-2x+43\leq 3$$

Subtract 43 from both sides.

$$-2x\leq 3-43$$

Subtract 43 from 3 to get -40.

$$-2x\leq -40$$

Divide both sides by -2. Since -2 is negative, the inequality direction is changed.

$$x\geq \frac{-40}{-2}$$

Divide -40 by -2 to get 20.

$$x\geq 20$$