Solve 4x+3y+50=0.quad

$$4 x + 3 y + 50 = 0 . \quad$$

Solve for x

$$x=-\frac{3y}{4}-\frac{25}{2}$$

Steps for Solving Linear Equation

Subtract 3y from both sides. Anything subtracted from zero gives its negation.

$$4x+50=-3y$$

Subtract 50 from both sides.

$$4x=-3y-50$$

Divide both sides by 4.

$$\frac{4x}{4}=\frac{-3y-50}{4}$$

Dividing by 4 undoes the multiplication by 4.

$$x=\frac{-3y-50}{4}$$

Divide -3y-50 by 4.

$$x=-\frac{3y}{4}-\frac{25}{2}$$

Solve for y

$$y=\frac{-4x-50}{3}$$

Steps for Solving Linear Equation

Subtract 4x from both sides. Anything subtracted from zero gives its negation.

$$3y+50=-4x$$

Subtract 50 from both sides.

$$3y=-4x-50$$

Divide both sides by 3.

$$\frac{3y}{3}=\frac{-4x-50}{3}$$

Dividing by 3 undoes the multiplication by 3.

$$y=\frac{-4x-50}{3}$$