Solve for x
x=\frac{3}{4}-3y
Solve for y
y=-\frac{x}{3}+\frac{1}{4}
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4x=3-12y
Subtract 12y from both sides.
\frac{4x}{4}=\frac{3-12y}{4}
Divide both sides by 4.
x=\frac{3-12y}{4}
Dividing by 4 undoes the multiplication by 4.
x=\frac{3}{4}-3y
Divide 3-12y by 4.
12y=3-4x
Subtract 4x from both sides.
\frac{12y}{12}=\frac{3-4x}{12}
Divide both sides by 12.
y=\frac{3-4x}{12}
Dividing by 12 undoes the multiplication by 12.
y=-\frac{x}{3}+\frac{1}{4}
Divide 3-4x by 12.
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