Solve for x
x=\frac{y}{4}+\frac{3}{8}
Solve for y
y=4x-\frac{3}{2}
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4x-\frac{3}{2}=y
Subtract 2 from \frac{1}{2} to get -\frac{3}{2}.
4x=y+\frac{3}{2}
Add \frac{3}{2} to both sides.
\frac{4x}{4}=\frac{y+\frac{3}{2}}{4}
Divide both sides by 4.
x=\frac{y+\frac{3}{2}}{4}
Dividing by 4 undoes the multiplication by 4.
x=\frac{y}{4}+\frac{3}{8}
Divide y+\frac{3}{2} by 4.
4x-\frac{3}{2}=y
Subtract 2 from \frac{1}{2} to get -\frac{3}{2}.
y=4x-\frac{3}{2}
Swap sides so that all variable terms are on the left hand side.
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