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4v^{2}+12v=0
Add 12v to both sides.
v\left(4v+12\right)=0
Factor out v.
v=0 v=-3
To find equation solutions, solve v=0 and 4v+12=0.
4v^{2}+12v=0
Add 12v to both sides.
v=\frac{-12±\sqrt{12^{2}}}{2\times 4}
This equation is in standard form: ax^{2}+bx+c=0. Substitute 4 for a, 12 for b, and 0 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.
v=\frac{-12±12}{2\times 4}
Take the square root of 12^{2}.
v=\frac{-12±12}{8}
Multiply 2 times 4.
v=\frac{0}{8}
Now solve the equation v=\frac{-12±12}{8} when ± is plus. Add -12 to 12.
v=0
Divide 0 by 8.
v=-\frac{24}{8}
Now solve the equation v=\frac{-12±12}{8} when ± is minus. Subtract 12 from -12.
v=-3
Divide -24 by 8.
v=0 v=-3
The equation is now solved.
4v^{2}+12v=0
Add 12v to both sides.
\frac{4v^{2}+12v}{4}=\frac{0}{4}
Divide both sides by 4.
v^{2}+\frac{12}{4}v=\frac{0}{4}
Dividing by 4 undoes the multiplication by 4.
v^{2}+3v=\frac{0}{4}
Divide 12 by 4.
v^{2}+3v=0
Divide 0 by 4.
v^{2}+3v+\left(\frac{3}{2}\right)^{2}=\left(\frac{3}{2}\right)^{2}
Divide 3, the coefficient of the x term, by 2 to get \frac{3}{2}. Then add the square of \frac{3}{2} to both sides of the equation. This step makes the left hand side of the equation a perfect square.
v^{2}+3v+\frac{9}{4}=\frac{9}{4}
Square \frac{3}{2} by squaring both the numerator and the denominator of the fraction.
\left(v+\frac{3}{2}\right)^{2}=\frac{9}{4}
Factor v^{2}+3v+\frac{9}{4}. In general, when x^{2}+bx+c is a perfect square, it can always be factored as \left(x+\frac{b}{2}\right)^{2}.
\sqrt{\left(v+\frac{3}{2}\right)^{2}}=\sqrt{\frac{9}{4}}
Take the square root of both sides of the equation.
v+\frac{3}{2}=\frac{3}{2} v+\frac{3}{2}=-\frac{3}{2}
Simplify.
v=0 v=-3
Subtract \frac{3}{2} from both sides of the equation.