Solve 4u^4v^-3*2vu^0

$$4 u ^ { 4 } v ^ { - 3 } \cdot 2 v u ^ { 0 }$$

Evaluate

$$\frac{8u^{4}}{v^{2}}$$

Steps Using Commutative Property of Multiplication

Use the rules of exponents to simplify the expression.

$$4^{1}u^{4}v^{-3}\times 2^{1}u^{0}v^{1}$$

Use the Commutative Property of Multiplication.

$$4^{1}\times 2^{1}u^{4}u^{0}v^{-3}v^{1}$$

To multiply powers of the same base, add their exponents.

$$4^{1}\times 2^{1}u^{4}v^{-3+1}$$

Add the exponents -3 and 1.

$$4^{1}\times 2^{1}u^{4}v^{-2}$$

Multiply 4 times 2.

$$8u^{4}\times \frac{1}{v^{2}}$$

Differentiate w.r.t. u

$$\frac{32u^{3}}{v^{2}}$$