Solve 4t-3/4>2

$$4 t - \frac { 3 } { 4 } > 2$$

Solve for t

$$t>\frac{11}{16}$$

Solution Steps

Add \frac{3}{4} to both sides.

$$4t>2+\frac{3}{4}$$

Convert 2 to fraction \frac{8}{4}.

$$4t>\frac{8}{4}+\frac{3}{4}$$

Since \frac{8}{4} and \frac{3}{4} have the same denominator, add them by adding their numerators.

$$4t>\frac{8+3}{4}$$

Add 8 and 3 to get 11.

$$4t>\frac{11}{4}$$

Divide both sides by 4. Since 4 is positive, the inequality direction remains the same.

$$t>\frac{\frac{11}{4}}{4}$$

Express \frac{\frac{11}{4}}{4} as a single fraction.

$$t>\frac{11}{4\times 4}$$

Multiply 4 and 4 to get 16.

$$t>\frac{11}{16}$$