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4q^{2}-28q+4q=0
Add 4q to both sides.
4q^{2}-24q=0
Combine -28q and 4q to get -24q.
q\left(4q-24\right)=0
Factor out q.
q=0 q=6
To find equation solutions, solve q=0 and 4q-24=0.
4q^{2}-28q+4q=0
Add 4q to both sides.
4q^{2}-24q=0
Combine -28q and 4q to get -24q.
q=\frac{-\left(-24\right)±\sqrt{\left(-24\right)^{2}}}{2\times 4}
This equation is in standard form: ax^{2}+bx+c=0. Substitute 4 for a, -24 for b, and 0 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.
q=\frac{-\left(-24\right)±24}{2\times 4}
Take the square root of \left(-24\right)^{2}.
q=\frac{24±24}{2\times 4}
The opposite of -24 is 24.
q=\frac{24±24}{8}
Multiply 2 times 4.
q=\frac{48}{8}
Now solve the equation q=\frac{24±24}{8} when ± is plus. Add 24 to 24.
q=6
Divide 48 by 8.
q=\frac{0}{8}
Now solve the equation q=\frac{24±24}{8} when ± is minus. Subtract 24 from 24.
q=0
Divide 0 by 8.
q=6 q=0
The equation is now solved.
4q^{2}-28q+4q=0
Add 4q to both sides.
4q^{2}-24q=0
Combine -28q and 4q to get -24q.
\frac{4q^{2}-24q}{4}=\frac{0}{4}
Divide both sides by 4.
q^{2}+\left(-\frac{24}{4}\right)q=\frac{0}{4}
Dividing by 4 undoes the multiplication by 4.
q^{2}-6q=\frac{0}{4}
Divide -24 by 4.
q^{2}-6q=0
Divide 0 by 4.
q^{2}-6q+\left(-3\right)^{2}=\left(-3\right)^{2}
Divide -6, the coefficient of the x term, by 2 to get -3. Then add the square of -3 to both sides of the equation. This step makes the left hand side of the equation a perfect square.
q^{2}-6q+9=9
Square -3.
\left(q-3\right)^{2}=9
Factor q^{2}-6q+9. In general, when x^{2}+bx+c is a perfect square, it can always be factored as \left(x+\frac{b}{2}\right)^{2}.
\sqrt{\left(q-3\right)^{2}}=\sqrt{9}
Take the square root of both sides of the equation.
q-3=3 q-3=-3
Simplify.
q=6 q=0
Add 3 to both sides of the equation.