Solve 4n(2n+5)-3(3n^2-6n+4)

$$4 n ( 2 n + 5 ) - 3 ( 3 n ^ { 2 } - 6 n + 4 )$$

Evaluate

$$-n^{2}+38n-12$$

Solution Steps

Use the distributive property to multiply 4n by 2n+5.

$$8n^{2}+20n-3\left(3n^{2}-6n+4\right)$$

Use the distributive property to multiply -3 by 3n^{2}-6n+4.

$$8n^{2}+20n-9n^{2}+18n-12$$

Combine 8n^{2} and -9n^{2} to get -n^{2}.

$$-n^{2}+20n+18n-12$$

Combine 20n and 18n to get 38n.

$$-n^{2}+38n-12$$

Expand

$$-n^{2}+38n-12$$

Solution Steps

Use the distributive property to multiply 4n by 2n+5.

$$8n^{2}+20n-3\left(3n^{2}-6n+4\right)$$

Use the distributive property to multiply -3 by 3n^{2}-6n+4.

$$8n^{2}+20n-9n^{2}+18n-12$$

Combine 8n^{2} and -9n^{2} to get -n^{2}.

$$-n^{2}+20n+18n-12$$

Combine 20n and 18n to get 38n.

$$-n^{2}+38n-12$$