Solve for k
k=\sqrt{17}+3\approx 7.123105626
k=3-\sqrt{17}\approx -1.123105626
Share
Copied to clipboard
4k^{2}-24k-32=0
All equations of the form ax^{2}+bx+c=0 can be solved using the quadratic formula: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. The quadratic formula gives two solutions, one when ± is addition and one when it is subtraction.
k=\frac{-\left(-24\right)±\sqrt{\left(-24\right)^{2}-4\times 4\left(-32\right)}}{2\times 4}
This equation is in standard form: ax^{2}+bx+c=0. Substitute 4 for a, -24 for b, and -32 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.
k=\frac{-\left(-24\right)±\sqrt{576-4\times 4\left(-32\right)}}{2\times 4}
Square -24.
k=\frac{-\left(-24\right)±\sqrt{576-16\left(-32\right)}}{2\times 4}
Multiply -4 times 4.
k=\frac{-\left(-24\right)±\sqrt{576+512}}{2\times 4}
Multiply -16 times -32.
k=\frac{-\left(-24\right)±\sqrt{1088}}{2\times 4}
Add 576 to 512.
k=\frac{-\left(-24\right)±8\sqrt{17}}{2\times 4}
Take the square root of 1088.
k=\frac{24±8\sqrt{17}}{2\times 4}
The opposite of -24 is 24.
k=\frac{24±8\sqrt{17}}{8}
Multiply 2 times 4.
k=\frac{8\sqrt{17}+24}{8}
Now solve the equation k=\frac{24±8\sqrt{17}}{8} when ± is plus. Add 24 to 8\sqrt{17}.
k=\sqrt{17}+3
Divide 24+8\sqrt{17} by 8.
k=\frac{24-8\sqrt{17}}{8}
Now solve the equation k=\frac{24±8\sqrt{17}}{8} when ± is minus. Subtract 8\sqrt{17} from 24.
k=3-\sqrt{17}
Divide 24-8\sqrt{17} by 8.
k=\sqrt{17}+3 k=3-\sqrt{17}
The equation is now solved.
4k^{2}-24k-32=0
Quadratic equations such as this one can be solved by completing the square. In order to complete the square, the equation must first be in the form x^{2}+bx=c.
4k^{2}-24k-32-\left(-32\right)=-\left(-32\right)
Add 32 to both sides of the equation.
4k^{2}-24k=-\left(-32\right)
Subtracting -32 from itself leaves 0.
4k^{2}-24k=32
Subtract -32 from 0.
\frac{4k^{2}-24k}{4}=\frac{32}{4}
Divide both sides by 4.
k^{2}+\left(-\frac{24}{4}\right)k=\frac{32}{4}
Dividing by 4 undoes the multiplication by 4.
k^{2}-6k=\frac{32}{4}
Divide -24 by 4.
k^{2}-6k=8
Divide 32 by 4.
k^{2}-6k+\left(-3\right)^{2}=8+\left(-3\right)^{2}
Divide -6, the coefficient of the x term, by 2 to get -3. Then add the square of -3 to both sides of the equation. This step makes the left hand side of the equation a perfect square.
k^{2}-6k+9=8+9
Square -3.
k^{2}-6k+9=17
Add 8 to 9.
\left(k-3\right)^{2}=17
Factor k^{2}-6k+9. In general, when x^{2}+bx+c is a perfect square, it can always be factored as \left(x+\frac{b}{2}\right)^{2}.
\sqrt{\left(k-3\right)^{2}}=\sqrt{17}
Take the square root of both sides of the equation.
k-3=\sqrt{17} k-3=-\sqrt{17}
Simplify.
k=\sqrt{17}+3 k=3-\sqrt{17}
Add 3 to both sides of the equation.
x ^ 2 -6x -8 = 0
Quadratic equations such as this one can be solved by a new direct factoring method that does not require guess work. To use the direct factoring method, the equation must be in the form x^2+Bx+C=0.This is achieved by dividing both sides of the equation by 4
r + s = 6 rs = -8
Let r and s be the factors for the quadratic equation such that x^2+Bx+C=(x−r)(x−s) where sum of factors (r+s)=−B and the product of factors rs = C
r = 3 - u s = 3 + u
Two numbers r and s sum up to 6 exactly when the average of the two numbers is \frac{1}{2}*6 = 3. You can also see that the midpoint of r and s corresponds to the axis of symmetry of the parabola represented by the quadratic equation y=x^2+Bx+C. The values of r and s are equidistant from the center by an unknown quantity u. Express r and s with respect to variable u. <div style='padding: 8px'><img src='https://opalmath.azureedge.net/customsolver/quadraticgraph.png' style='width: 100%;max-width: 700px' /></div>
(3 - u) (3 + u) = -8
To solve for unknown quantity u, substitute these in the product equation rs = -8
9 - u^2 = -8
Simplify by expanding (a -b) (a + b) = a^2 – b^2
-u^2 = -8-9 = -17
Simplify the expression by subtracting 9 on both sides
u^2 = 17 u = \pm\sqrt{17} = \pm \sqrt{17}
Simplify the expression by multiplying -1 on both sides and take the square root to obtain the value of unknown variable u
r =3 - \sqrt{17} = -1.123 s = 3 + \sqrt{17} = 7.123
The factors r and s are the solutions to the quadratic equation. Substitute the value of u to compute the r and s.
Examples
Quadratic equation
{ x } ^ { 2 } - 4 x - 5 = 0
Trigonometry
4 \sin \theta \cos \theta = 2 \sin \theta
Linear equation
y = 3x + 4
Arithmetic
699 * 533
Matrix
\left[ \begin{array} { l l } { 2 } & { 3 } \\ { 5 } & { 4 } \end{array} \right] \left[ \begin{array} { l l l } { 2 } & { 0 } & { 3 } \\ { -1 } & { 1 } & { 5 } \end{array} \right]
Simultaneous equation
\left. \begin{cases} { 8x+2y = 46 } \\ { 7x+3y = 47 } \end{cases} \right.
Differentiation
\frac { d } { d x } \frac { ( 3 x ^ { 2 } - 2 ) } { ( x - 5 ) }
Integration
\int _ { 0 } ^ { 1 } x e ^ { - x ^ { 2 } } d x
Limits
\lim _{x \rightarrow-3} \frac{x^{2}-9}{x^{2}+2 x-3}