Solve 4e-3D+F-2y=0

$$4 e - 3 D + F - 2 y = 0$$

Solve for D

$$D=\frac{4e+F-2y}{3}$$

Steps for Solving Linear Equation

Subtract 4e from both sides. Anything subtracted from zero gives its negation.

$$-3D+F-2y=-4e$$

Subtract F from both sides.

$$-3D-2y=-4e-F$$

Add 2y to both sides.

$$-3D=-4e-F+2y$$

The equation is in standard form.

$$-3D=2y-F-4e$$

Divide both sides by -3.

$$\frac{-3D}{-3}=\frac{2y-F-4e}{-3}$$

Dividing by -3 undoes the multiplication by -3.

$$D=\frac{2y-F-4e}{-3}$$

Divide -4e-F+2y by -3.

$$D=\frac{4e+F-2y}{3}$$

Solve for F

$$F=2y+3D-4e$$