Solve 4a-3b=c

$$4 a - 3 b = c$$

Solve for a

$$a=\frac{3b+c}{4}$$

Steps for Solving Linear Equation

Add 3b to both sides.

$$4a=c+3b$$

The equation is in standard form.

$$4a=3b+c$$

Divide both sides by 4.

$$\frac{4a}{4}=\frac{3b+c}{4}$$

Dividing by 4 undoes the multiplication by 4.

$$a=\frac{3b+c}{4}$$

Solve for b

$$b=\frac{4a-c}{3}$$

Steps for Solving Linear Equation

Subtract 4a from both sides.

$$-3b=c-4a$$

Divide both sides by -3.

$$\frac{-3b}{-3}=\frac{c-4a}{-3}$$

Dividing by -3 undoes the multiplication by -3.

$$b=\frac{c-4a}{-3}$$

Divide c-4a by -3.

$$b=\frac{4a-c}{3}$$