Solve 4a*(-2a)=

$$4 a \times ( - 2 a ) =$$

Evaluate

$$-8a^{2}$$

Solution Steps

Multiply a and a to get a^{2}.

$$4a^{2}\left(-2\right)$$

Multiply 4 and -2 to get -8.

$$-8a^{2}$$

Differentiate w.r.t. a

$$-16a$$

Steps Using Definition of a Derivative

Multiply a and a to get a^{2}.

$$\frac{\mathrm{d}}{\mathrm{d}a}(4a^{2}\left(-2\right))$$

Multiply 4 and -2 to get -8.

$$\frac{\mathrm{d}}{\mathrm{d}a}(-8a^{2})$$

The derivative of ax^{n} is nax^{n-1}.

$$2\left(-8\right)a^{2-1}$$

Multiply 2 times -8.

$$-16a^{2-1}$$

Subtract 1 from 2.

$$-16a^{1}$$

For any term t, t^{1}=t.

$$-16a$$