Solve for a
a=-\frac{3b}{2}+2
Solve for b
b=\frac{4-2a}{3}
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4a+3=11-6b
Subtract 6b from both sides.
4a=11-6b-3
Subtract 3 from both sides.
4a=8-6b
Subtract 3 from 11 to get 8.
\frac{4a}{4}=\frac{8-6b}{4}
Divide both sides by 4.
a=\frac{8-6b}{4}
Dividing by 4 undoes the multiplication by 4.
a=-\frac{3b}{2}+2
Divide 8-6b by 4.
6b+3=11-4a
Subtract 4a from both sides.
6b=11-4a-3
Subtract 3 from both sides.
6b=8-4a
Subtract 3 from 11 to get 8.
\frac{6b}{6}=\frac{8-4a}{6}
Divide both sides by 6.
b=\frac{8-4a}{6}
Dividing by 6 undoes the multiplication by 6.
b=\frac{4-2a}{3}
Divide 8-4a by 6.
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