Solve 4a+3c=17c

$$4 a + 3 c = 17 c$$

Solve for a

$$a=\frac{7c}{2}$$

Steps for Solving Linear Equation

Subtract 3c from both sides.

$$4a=17c-3c$$

Combine 17c and -3c to get 14c.

$$4a=14c$$

Divide both sides by 4.

$$\frac{4a}{4}=\frac{14c}{4}$$

Dividing by 4 undoes the multiplication by 4.

$$a=\frac{14c}{4}$$

Divide 14c by 4.

$$a=\frac{7c}{2}$$

Solve for c

$$c=\frac{2a}{7}$$

Steps for Solving Linear Equation

Subtract 17c from both sides.

$$4a+3c-17c=0$$

Combine 3c and -17c to get -14c.

$$4a-14c=0$$

Subtract 4a from both sides. Anything subtracted from zero gives its negation.

$$-14c=-4a$$

Divide both sides by -14.

$$\frac{-14c}{-14}=-\frac{4a}{-14}$$

Dividing by -14 undoes the multiplication by -14.

$$c=-\frac{4a}{-14}$$

Divide -4a by -14.

$$c=\frac{2a}{7}$$