Solve 4a+3mu+5a-6=9quada+2b

$$4 a + 3 \mu + 5 a - 6 = 9 \quad a + 2 b$$

Solve for b

$$b=\frac{3\left(\mu -2\right)}{2}$$

Steps for Solving Linear Equation

Combine 4a and 5a to get 9a.

$$9a+3\mu -6=9a+2b$$

Swap sides so that all variable terms are on the left hand side.

$$9a+2b=9a+3\mu -6$$

Subtract 9a from both sides.

$$2b=9a+3\mu -6-9a$$

Combine 9a and -9a to get 0.

$$2b=3\mu -6$$

Divide both sides by 2.

$$\frac{2b}{2}=\frac{3\mu -6}{2}$$

Dividing by 2 undoes the multiplication by 2.

$$b=\frac{3\mu -6}{2}$$

Divide -6+3\mu by 2.

$$b=\frac{3\mu }{2}-3$$

Solve for a

$$a\in \mathrm{R}$$

$$\mu =\frac{2b}{3}+2$$