Solve 4-6(x+3)leq-8+4x

$$4 - 6 ( x + 3 ) \leq - 8 + 4 x$$

Solve for x

$$x\geq -\frac{3}{5}$$

Solution Steps

Use the distributive property to multiply -6 by x+3.

$$4-6x-18\leq -8+4x$$

Subtract 18 from 4 to get -14.

$$-14-6x\leq -8+4x$$

Subtract 4x from both sides.

$$-14-6x-4x\leq -8$$

Combine -6x and -4x to get -10x.

$$-14-10x\leq -8$$

Add 14 to both sides.

$$-10x\leq -8+14$$

Add -8 and 14 to get 6.

$$-10x\leq 6$$

Divide both sides by -10. Since -10 is negative, the inequality direction is changed.

$$x\geq \frac{6}{-10}$$

Reduce the fraction \frac{6}{-10} to lowest terms by extracting and canceling out 2.

$$x\geq -\frac{3}{5}$$