Solve for x
x=\frac{3\left(y-8\right)}{8}
Solve for y
y=\frac{8\left(x+3\right)}{3}
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-20-8x=4-3y
Swap sides so that all variable terms are on the left hand side.
-8x=4-3y+20
Add 20 to both sides.
-8x=24-3y
Add 4 and 20 to get 24.
\frac{-8x}{-8}=\frac{24-3y}{-8}
Divide both sides by -8.
x=\frac{24-3y}{-8}
Dividing by -8 undoes the multiplication by -8.
x=\frac{3y}{8}-3
Divide 24-3y by -8.
-3y=-20-8x-4
Subtract 4 from both sides.
-3y=-24-8x
Subtract 4 from -20 to get -24.
-3y=-8x-24
The equation is in standard form.
\frac{-3y}{-3}=\frac{-8x-24}{-3}
Divide both sides by -3.
y=\frac{-8x-24}{-3}
Dividing by -3 undoes the multiplication by -3.
y=\frac{8x}{3}+8
Divide -24-8x by -3.
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