Solve 4-3-5+10div2sqrt{25}+8^3+(-3)+1+2[-3+(-2+6)]^2

$$4 - 3 - 5 + 10 \div 2 \sqrt { 25 } + 8 ^ { 3 } + ( - 3 ) + \{ 1 + 2 [ - 3 + ( - 2 + 6 ) ] \} ^ { 2 }$$

Evaluate

$$539$$

Solution Steps

Subtract 3 from 4 to get 1.

$$1-5+\frac{10}{2}\sqrt{25}+8^{3}-3+\left(1+2\left(-3-2+6\right)\right)^{2}$$

Subtract 5 from 1 to get -4.

$$-4+\frac{10}{2}\sqrt{25}+8^{3}-3+\left(1+2\left(-3-2+6\right)\right)^{2}$$

Divide 10 by 2 to get 5.

$$-4+5\sqrt{25}+8^{3}-3+\left(1+2\left(-3-2+6\right)\right)^{2}$$

Calculate the square root of 25 and get 5.

$$-4+5\times 5+8^{3}-3+\left(1+2\left(-3-2+6\right)\right)^{2}$$

Multiply 5 and 5 to get 25.

$$-4+25+8^{3}-3+\left(1+2\left(-3-2+6\right)\right)^{2}$$

Add -4 and 25 to get 21.

$$21+8^{3}-3+\left(1+2\left(-3-2+6\right)\right)^{2}$$

Calculate 8 to the power of 3 and get 512.

$$21+512-3+\left(1+2\left(-3-2+6\right)\right)^{2}$$

Add 21 and 512 to get 533.

$$533-3+\left(1+2\left(-3-2+6\right)\right)^{2}$$

Subtract 3 from 533 to get 530.

$$530+\left(1+2\left(-3-2+6\right)\right)^{2}$$

Subtract 2 from -3 to get -5.

$$530+\left(1+2\left(-5+6\right)\right)^{2}$$

Add -5 and 6 to get 1.

$$530+\left(1+2\times 1\right)^{2}$$

Multiply 2 and 1 to get 2.

$$530+\left(1+2\right)^{2}$$

Add 1 and 2 to get 3.

$$530+3^{2}$$

Calculate 3 to the power of 2 and get 9.

$$530+9$$

Add 530 and 9 to get 539.

$$539$$

Factor

$$7^{2}\times 11$$