Solve 4-3^2+3+2^3-3^2-2+2^5

$$4 - 3 ^ { 2 } + 3 + 2 ^ { 3 } - 3 ^ { 2 } - 2 + 2 ^ { 5 }$$

Evaluate

$$27$$

Solution Steps

Calculate 3 to the power of 2 and get 9.

$$4-9+3+2^{3}-3^{2}-2+2^{5}$$

Subtract 9 from 4 to get -5.

$$-5+3+2^{3}-3^{2}-2+2^{5}$$

Add -5 and 3 to get -2.

$$-2+2^{3}-3^{2}-2+2^{5}$$

Calculate 2 to the power of 3 and get 8.

$$-2+8-3^{2}-2+2^{5}$$

Add -2 and 8 to get 6.

$$6-3^{2}-2+2^{5}$$

Calculate 3 to the power of 2 and get 9.

$$6-9-2+2^{5}$$

Subtract 9 from 6 to get -3.

$$-3-2+2^{5}$$

Subtract 2 from -3 to get -5.

$$-5+2^{5}$$

Calculate 2 to the power of 5 and get 32.

$$-5+32$$

Add -5 and 32 to get 27.

$$27$$

Factor

$$3^{3}$$