Solve 4(x+3)^2=20

$$4 ( x + 3 ) ^ { 2 } = 20$$

Solve for x

$$x=\sqrt{5}-3\approx -0.763932023$$

$$x=-\left(\sqrt{5}+3\right)\approx -5.236067977$$

Steps by Finding Square Root

Divide both sides by 4.

$$\frac{4\left(x+3\right)^{2}}{4}=\frac{20}{4}$$

Dividing by 4 undoes the multiplication by 4.

$$\left(x+3\right)^{2}=\frac{20}{4}$$

Divide 20 by 4.

$$\left(x+3\right)^{2}=5$$

Take the square root of both sides of the equation.

$$x+3=\sqrt{5} x+3=-\sqrt{5}$$

Subtract 3 from both sides of the equation.

$$x+3-3=\sqrt{5}-3 x+3-3=-\sqrt{5}-3$$

Subtracting 3 from itself leaves 0.

$$x=\sqrt{5}-3 x=-\sqrt{5}-3$$