Solve 4(3x-1)>12+8(x-1)

$$4 ( 3 x - 1 ) > 12 + 8 ( x - 1 )$$

Solve for x

$$x>2$$

Solution Steps

Use the distributive property to multiply 4 by 3x-1.

$$12x-4>12+8\left(x-1\right)$$

Use the distributive property to multiply 8 by x-1.

$$12x-4>12+8x-8$$

Subtract 8 from 12 to get 4.

$$12x-4>4+8x$$

Subtract 8x from both sides.

$$12x-4-8x>4$$

Combine 12x and -8x to get 4x.

$$4x-4>4$$

Add 4 to both sides.

$$4x>4+4$$

Add 4 and 4 to get 8.

$$4x>8$$

Divide both sides by 4. Since 4 is positive, the inequality direction remains the same.

$$x>\frac{8}{4}$$

Divide 8 by 4 to get 2.

$$x>2$$