Solve 4(3-x)+5<7x-1=

$$4 ( 3 - x ) + 5 < 7 x - 1 =$$

Solve for x

$$x>\frac{18}{11}$$

Solution Steps

Use the distributive property to multiply 4 by 3-x.

$$12-4x+5<7x-1$$

Add 12 and 5 to get 17.

$$17-4x<7x-1$$

Subtract 7x from both sides.

$$17-4x-7x<-1$$

Combine -4x and -7x to get -11x.

$$17-11x<-1$$

Subtract 17 from both sides.

$$-11x<-1-17$$

Subtract 17 from -1 to get -18.

$$-11x<-18$$

Divide both sides by -11. Since -11 is negative, the inequality direction is changed.

$$x>\frac{-18}{-11}$$

Fraction \frac{-18}{-11} can be simplified to \frac{18}{11} by removing the negative sign from both the numerator and the denominator.

$$x>\frac{18}{11}$$