Solve 4(-1/4)^2+21(-1/4)+5

$$4 ( - \frac { 1 } { 4 } ) ^ { 2 } + 21 ( - \frac { 1 } { 4 } ) + 5$$

Evaluate

$$0$$

Solution Steps

Calculate -\frac{1}{4} to the power of 2 and get \frac{1}{16}.

$$4\times \frac{1}{16}+21\left(-\frac{1}{4}\right)+5$$

Multiply 4 and \frac{1}{16} to get \frac{4}{16}.

$$\frac{4}{16}+21\left(-\frac{1}{4}\right)+5$$

Reduce the fraction \frac{4}{16} to lowest terms by extracting and canceling out 4.

$$\frac{1}{4}+21\left(-\frac{1}{4}\right)+5$$

Express 21\left(-\frac{1}{4}\right) as a single fraction.

$$\frac{1}{4}+\frac{21\left(-1\right)}{4}+5$$

Multiply 21 and -1 to get -21.

$$\frac{1}{4}+\frac{-21}{4}+5$$

Fraction \frac{-21}{4} can be rewritten as -\frac{21}{4} by extracting the negative sign.

$$\frac{1}{4}-\frac{21}{4}+5$$

Since \frac{1}{4} and \frac{21}{4} have the same denominator, subtract them by subtracting their numerators.

$$\frac{1-21}{4}+5$$

Subtract 21 from 1 to get -20.

$$\frac{-20}{4}+5$$

Divide -20 by 4 to get -5.

$$-5+5$$

Add -5 and 5 to get 0.

$$0$$

Factor

$$0$$