Solve 4(14/3)+17-8(14/3)+15(14/3)=3-5(14/3)

$$4 ( \frac { 14 } { 3 } ) + 17 - 8 ( \frac { 14 } { 3 } ) + 15 ( \frac { 14 } { 3 } ) = 3 - 5 ( \frac { 14 } { 3 } )$$

Verify

Solution Steps

Express 4\times \frac{14}{3} as a single fraction.

$$\frac{4\times 14}{3}+17-8\times \frac{14}{3}+15\times \frac{14}{3}=3-5\times \frac{14}{3}$$

Multiply 4 and 14 to get 56.

$$\frac{56}{3}+17-8\times \frac{14}{3}+15\times \frac{14}{3}=3-5\times \frac{14}{3}$$

Convert 17 to fraction \frac{51}{3}.

$$\frac{56}{3}+\frac{51}{3}-8\times \frac{14}{3}+15\times \frac{14}{3}=3-5\times \frac{14}{3}$$

Since \frac{56}{3} and \frac{51}{3} have the same denominator, add them by adding their numerators.

$$\frac{56+51}{3}-8\times \frac{14}{3}+15\times \frac{14}{3}=3-5\times \frac{14}{3}$$

Add 56 and 51 to get 107.

$$\frac{107}{3}-8\times \frac{14}{3}+15\times \frac{14}{3}=3-5\times \frac{14}{3}$$

Express 8\times \frac{14}{3} as a single fraction.

$$\frac{107}{3}-\frac{8\times 14}{3}+15\times \frac{14}{3}=3-5\times \frac{14}{3}$$

Multiply 8 and 14 to get 112.

$$\frac{107}{3}-\frac{112}{3}+15\times \frac{14}{3}=3-5\times \frac{14}{3}$$

Since \frac{107}{3} and \frac{112}{3} have the same denominator, subtract them by subtracting their numerators.

$$\frac{107-112}{3}+15\times \frac{14}{3}=3-5\times \frac{14}{3}$$

Subtract 112 from 107 to get -5.

$$-\frac{5}{3}+15\times \frac{14}{3}=3-5\times \frac{14}{3}$$

Express 15\times \frac{14}{3} as a single fraction.

$$-\frac{5}{3}+\frac{15\times 14}{3}=3-5\times \frac{14}{3}$$

Multiply 15 and 14 to get 210.

$$-\frac{5}{3}+\frac{210}{3}=3-5\times \frac{14}{3}$$

Since -\frac{5}{3} and \frac{210}{3} have the same denominator, add them by adding their numerators.

$$\frac{-5+210}{3}=3-5\times \frac{14}{3}$$

Add -5 and 210 to get 205.

$$\frac{205}{3}=3-5\times \frac{14}{3}$$

Express 5\times \frac{14}{3} as a single fraction.

$$\frac{205}{3}=3-\frac{5\times 14}{3}$$

Multiply 5 and 14 to get 70.

$$\frac{205}{3}=3-\frac{70}{3}$$

Convert 3 to fraction \frac{9}{3}.

$$\frac{205}{3}=\frac{9}{3}-\frac{70}{3}$$

Since \frac{9}{3} and \frac{70}{3} have the same denominator, subtract them by subtracting their numerators.

$$\frac{205}{3}=\frac{9-70}{3}$$

Subtract 70 from 9 to get -61.

$$\frac{205}{3}=-\frac{61}{3}$$

Compare \frac{205}{3} and -\frac{61}{3}.

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