Solve 4(1/2)^8*2^9*(-8)^3

$$4 ( \frac { 1 } { 2 } ) ^ { 8 } \times 2 ^ { 9 } \times ( - 8 ) ^ { 3 }$$

Evaluate

$$-4096$$

Solution Steps

Calculate \frac{1}{2} to the power of 8 and get \frac{1}{256}.

$$4\times \frac{1}{256}\times 2^{9}\left(-8\right)^{3}$$

Multiply 4 and \frac{1}{256} to get \frac{4}{256}.

$$\frac{4}{256}\times 2^{9}\left(-8\right)^{3}$$

Reduce the fraction \frac{4}{256} to lowest terms by extracting and canceling out 4.

$$\frac{1}{64}\times 2^{9}\left(-8\right)^{3}$$

Calculate 2 to the power of 9 and get 512.

$$\frac{1}{64}\times 512\left(-8\right)^{3}$$

Multiply \frac{1}{64} and 512 to get \frac{512}{64}.

$$\frac{512}{64}\left(-8\right)^{3}$$

Divide 512 by 64 to get 8.

$$8\left(-8\right)^{3}$$

Calculate -8 to the power of 3 and get -512.

$$8\left(-512\right)$$

Multiply 8 and -512 to get -4096.

$$-4096$$

Factor

$$-4096$$