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4x^{4}-37x^{2}+9=0
To factor the expression, solve the equation where it equals to 0.
±\frac{9}{4},±\frac{9}{2},±9,±\frac{3}{4},±\frac{3}{2},±3,±\frac{1}{4},±\frac{1}{2},±1
By Rational Root Theorem, all rational roots of a polynomial are in the form \frac{p}{q}, where p divides the constant term 9 and q divides the leading coefficient 4. List all candidates \frac{p}{q}.
x=3
Find one such root by trying out all the integer values, starting from the smallest by absolute value. If no integer roots are found, try out fractions.
4x^{3}+12x^{2}-x-3=0
By Factor theorem, x-k is a factor of the polynomial for each root k. Divide 4x^{4}-37x^{2}+9 by x-3 to get 4x^{3}+12x^{2}-x-3. To factor the result, solve the equation where it equals to 0.
±\frac{3}{4},±\frac{3}{2},±3,±\frac{1}{4},±\frac{1}{2},±1
By Rational Root Theorem, all rational roots of a polynomial are in the form \frac{p}{q}, where p divides the constant term -3 and q divides the leading coefficient 4. List all candidates \frac{p}{q}.
x=-3
Find one such root by trying out all the integer values, starting from the smallest by absolute value. If no integer roots are found, try out fractions.
4x^{2}-1=0
By Factor theorem, x-k is a factor of the polynomial for each root k. Divide 4x^{3}+12x^{2}-x-3 by x+3 to get 4x^{2}-1. To factor the result, solve the equation where it equals to 0.
x=\frac{0±\sqrt{0^{2}-4\times 4\left(-1\right)}}{2\times 4}
All equations of the form ax^{2}+bx+c=0 can be solved using the quadratic formula: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. Substitute 4 for a, 0 for b, and -1 for c in the quadratic formula.
x=\frac{0±4}{8}
Do the calculations.
x=-\frac{1}{2} x=\frac{1}{2}
Solve the equation 4x^{2}-1=0 when ± is plus and when ± is minus.
\left(x-3\right)\left(2x-1\right)\left(x+3\right)\left(2x+1\right)
Rewrite the factored expression using the obtained roots.