Solve for x
x = \frac{5}{2} = 2\frac{1}{2} = 2.5
x = -\frac{5}{2} = -2\frac{1}{2} = -2.5
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4x^{2}-9-16=0
Subtract 16 from both sides.
4x^{2}-25=0
Subtract 16 from -9 to get -25.
\left(2x-5\right)\left(2x+5\right)=0
Consider 4x^{2}-25. Rewrite 4x^{2}-25 as \left(2x\right)^{2}-5^{2}. The difference of squares can be factored using the rule: a^{2}-b^{2}=\left(a-b\right)\left(a+b\right).
x=\frac{5}{2} x=-\frac{5}{2}
To find equation solutions, solve 2x-5=0 and 2x+5=0.
4x^{2}=16+9
Add 9 to both sides.
4x^{2}=25
Add 16 and 9 to get 25.
x^{2}=\frac{25}{4}
Divide both sides by 4.
x=\frac{5}{2} x=-\frac{5}{2}
Take the square root of both sides of the equation.
4x^{2}-9-16=0
Subtract 16 from both sides.
4x^{2}-25=0
Subtract 16 from -9 to get -25.
x=\frac{0±\sqrt{0^{2}-4\times 4\left(-25\right)}}{2\times 4}
This equation is in standard form: ax^{2}+bx+c=0. Substitute 4 for a, 0 for b, and -25 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.
x=\frac{0±\sqrt{-4\times 4\left(-25\right)}}{2\times 4}
Square 0.
x=\frac{0±\sqrt{-16\left(-25\right)}}{2\times 4}
Multiply -4 times 4.
x=\frac{0±\sqrt{400}}{2\times 4}
Multiply -16 times -25.
x=\frac{0±20}{2\times 4}
Take the square root of 400.
x=\frac{0±20}{8}
Multiply 2 times 4.
x=\frac{5}{2}
Now solve the equation x=\frac{0±20}{8} when ± is plus. Reduce the fraction \frac{20}{8} to lowest terms by extracting and canceling out 4.
x=-\frac{5}{2}
Now solve the equation x=\frac{0±20}{8} when ± is minus. Reduce the fraction \frac{-20}{8} to lowest terms by extracting and canceling out 4.
x=\frac{5}{2} x=-\frac{5}{2}
The equation is now solved.
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y = 3x + 4
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Matrix
\left[ \begin{array} { l l } { 2 } & { 3 } \\ { 5 } & { 4 } \end{array} \right] \left[ \begin{array} { l l l } { 2 } & { 0 } & { 3 } \\ { -1 } & { 1 } & { 5 } \end{array} \right]
Simultaneous equation
\left. \begin{cases} { 8x+2y = 46 } \\ { 7x+3y = 47 } \end{cases} \right.
Differentiation
\frac { d } { d x } \frac { ( 3 x ^ { 2 } - 2 ) } { ( x - 5 ) }
Integration
\int _ { 0 } ^ { 1 } x e ^ { - x ^ { 2 } } d x
Limits
\lim _{x \rightarrow-3} \frac{x^{2}-9}{x^{2}+2 x-3}