Solve 4x^2-20x+2x+40-4x^2+64x-256=0

$$4 { x }^{ 2 } -20x+2x+40-4 { x }^{ 2 } +64x-256=0$$

Solve for x

$$x = \frac{108}{23} = 4\frac{16}{23} \approx 4.695652174$$

Steps for Solving Linear Equation

Combine -20x and 2x to get -18x.

$$4x^{2}-18x+40-4x^{2}+64x-256=0$$

Combine 4x^{2} and -4x^{2} to get 0.

$$-18x+40+64x-256=0$$

Combine -18x and 64x to get 46x.

$$46x+40-256=0$$

Subtract 256 from 40 to get -216.

$$46x-216=0$$

Add 216 to both sides. Anything plus zero gives itself.

$$46x=216$$

Divide both sides by 46.

$$x=\frac{216}{46}$$

Reduce the fraction \frac{216}{46} to lowest terms by extracting and canceling out 2.

$$x=\frac{108}{23}$$