Solve 4x^2+22c=0

$$4 { x }^{ 2 } +22c = 0$$

Solve for c

$$c=-\frac{2x^{2}}{11}$$

Steps for Solving Linear Equation

Subtract 4x^{2} from both sides. Anything subtracted from zero gives its negation.

$$22c=-4x^{2}$$

Divide both sides by 22.

$$\frac{22c}{22}=-\frac{4x^{2}}{22}$$

Dividing by 22 undoes the multiplication by 22.

$$c=-\frac{4x^{2}}{22}$$

Divide -4x^{2} by 22.

$$c=-\frac{2x^{2}}{11}$$

Solve for x (complex solution)

$$x=-\frac{i\sqrt{22c}}{2}$$

$$x=\frac{i\sqrt{22c}}{2}$$

Solve for x

$$x=\frac{\sqrt{-22c}}{2}$$

$$x=-\frac{\sqrt{-22c}}{2}\text{, }c\leq 0$$