Solve 4*4^3-12*4^2+y*4=0

$$4 \times { 4 }^{ 3 } -12 \times { 4 }^{ 2 } +y \times 4=0$$

Solve for y

$$y=-16$$

Steps for Solving Linear Equation

To multiply powers of the same base, add their exponents. Add 1 and 3 to get 4.

$$4^{4}-12\times 4^{2}+y\times 4=0$$

Calculate 4 to the power of 4 and get 256.

$$256-12\times 4^{2}+y\times 4=0$$

Calculate 4 to the power of 2 and get 16.

$$256-12\times 16+y\times 4=0$$

Multiply 12 and 16 to get 192.

$$256-192+y\times 4=0$$

Subtract 192 from 256 to get 64.

$$64+y\times 4=0$$

Subtract 64 from both sides. Anything subtracted from zero gives its negation.

$$y\times 4=-64$$

Divide both sides by 4.

$$y=\frac{-64}{4}$$

Divide -64 by 4 to get -16.

$$y=-16$$