Solve for f
f=-\frac{x}{4}+\frac{1}{4x}
x\neq 0
Solve for x
x=\sqrt{4f^{2}+1}-2f
x=-\sqrt{4f^{2}+1}-2f
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4xf=1-x^{2}
The equation is in standard form.
\frac{4xf}{4x}=\frac{1-x^{2}}{4x}
Divide both sides by 4x.
f=\frac{1-x^{2}}{4x}
Dividing by 4x undoes the multiplication by 4x.
f=-\frac{x}{4}+\frac{1}{4x}
Divide -x^{2}+1 by 4x.
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