Solve 4log48+9log50*4log3*log2

$$4 \log 48 + 9 \log 50 \cdot 4 \log 3 \cdot \log 2$$

Evaluate

$$\frac{18\ln(5)\ln(\ln(2))+27\ln(2)\ln(\ln(2))-18\ln(5)\ln(\ln(10))-27\ln(2)\ln(\ln(10))+22\ln(3)\ln(5)+\ln(2)\ln(6176733962839470000000000000000)}{\ln(10)^{2}}\approx 5.808186838$$

Factor

$$\frac{\log_{e} {(2)} {(27 \log_{e} {(\log_{e} {(2)})} + \log_{e} {(6176733962839470000000000000000)} - 27 \log_{e} {(\log_{e} {(10)})})} + \log_{e} {(5)} {(18 \log_{e} {(\log_{e} {(2)})} - 18 \log_{e} {(\log_{e} {(10)})} + 22 \log_{e} {(3)})}}{\log_{e} {(10)} ^ {2}} = 5.80818683810329$$