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Solve for x (complex solution)
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4x-4-x\left(x+4\right)=-2
Use the distributive property to multiply 4 by x-1.
4x-4-\left(x^{2}+4x\right)=-2
Use the distributive property to multiply x by x+4.
4x-4-x^{2}-4x=-2
To find the opposite of x^{2}+4x, find the opposite of each term.
-4-x^{2}=-2
Combine 4x and -4x to get 0.
-x^{2}=-2+4
Add 4 to both sides.
-x^{2}=2
Add -2 and 4 to get 2.
x^{2}=-2
Divide both sides by -1.
x=\sqrt{2}i x=-\sqrt{2}i
The equation is now solved.
4x-4-x\left(x+4\right)=-2
Use the distributive property to multiply 4 by x-1.
4x-4-\left(x^{2}+4x\right)=-2
Use the distributive property to multiply x by x+4.
4x-4-x^{2}-4x=-2
To find the opposite of x^{2}+4x, find the opposite of each term.
-4-x^{2}=-2
Combine 4x and -4x to get 0.
-4-x^{2}+2=0
Add 2 to both sides.
-2-x^{2}=0
Add -4 and 2 to get -2.
-x^{2}-2=0
Quadratic equations like this one, with an x^{2} term but no x term, can still be solved using the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}, once they are put in standard form: ax^{2}+bx+c=0.
x=\frac{0±\sqrt{0^{2}-4\left(-1\right)\left(-2\right)}}{2\left(-1\right)}
This equation is in standard form: ax^{2}+bx+c=0. Substitute -1 for a, 0 for b, and -2 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.
x=\frac{0±\sqrt{-4\left(-1\right)\left(-2\right)}}{2\left(-1\right)}
Square 0.
x=\frac{0±\sqrt{4\left(-2\right)}}{2\left(-1\right)}
Multiply -4 times -1.
x=\frac{0±\sqrt{-8}}{2\left(-1\right)}
Multiply 4 times -2.
x=\frac{0±2\sqrt{2}i}{2\left(-1\right)}
Take the square root of -8.
x=\frac{0±2\sqrt{2}i}{-2}
Multiply 2 times -1.
x=-\sqrt{2}i
Now solve the equation x=\frac{0±2\sqrt{2}i}{-2} when ± is plus.
x=\sqrt{2}i
Now solve the equation x=\frac{0±2\sqrt{2}i}{-2} when ± is minus.
x=-\sqrt{2}i x=\sqrt{2}i
The equation is now solved.