Solve 42/3+51/4-1/8-12/3

$$4 \frac{ 2 }{ 3 } +5 \frac{ 1 }{ 4 } - \frac{ 1 }{ 8 } -1 \frac{ 2 }{ 3 }$$

Evaluate

$$\frac{65}{8}=8.125$$

Solution Steps

Multiply 4 and 3 to get 12.

$$\frac{12+2}{3}+\frac{5\times 4+1}{4}-\frac{1}{8}-\frac{1\times 3+2}{3}$$

Add 12 and 2 to get 14.

$$\frac{14}{3}+\frac{5\times 4+1}{4}-\frac{1}{8}-\frac{1\times 3+2}{3}$$

Multiply 5 and 4 to get 20.

$$\frac{14}{3}+\frac{20+1}{4}-\frac{1}{8}-\frac{1\times 3+2}{3}$$

Add 20 and 1 to get 21.

$$\frac{14}{3}+\frac{21}{4}-\frac{1}{8}-\frac{1\times 3+2}{3}$$

Least common multiple of 3 and 4 is 12. Convert \frac{14}{3} and \frac{21}{4} to fractions with denominator 12.

$$\frac{56}{12}+\frac{63}{12}-\frac{1}{8}-\frac{1\times 3+2}{3}$$

Since \frac{56}{12} and \frac{63}{12} have the same denominator, add them by adding their numerators.

$$\frac{56+63}{12}-\frac{1}{8}-\frac{1\times 3+2}{3}$$

Add 56 and 63 to get 119.

$$\frac{119}{12}-\frac{1}{8}-\frac{1\times 3+2}{3}$$

Least common multiple of 12 and 8 is 24. Convert \frac{119}{12} and \frac{1}{8} to fractions with denominator 24.

$$\frac{238}{24}-\frac{3}{24}-\frac{1\times 3+2}{3}$$

Since \frac{238}{24} and \frac{3}{24} have the same denominator, subtract them by subtracting their numerators.

$$\frac{238-3}{24}-\frac{1\times 3+2}{3}$$

Subtract 3 from 238 to get 235.

$$\frac{235}{24}-\frac{1\times 3+2}{3}$$

Multiply 1 and 3 to get 3.

$$\frac{235}{24}-\frac{3+2}{3}$$

Add 3 and 2 to get 5.

$$\frac{235}{24}-\frac{5}{3}$$

Least common multiple of 24 and 3 is 24. Convert \frac{235}{24} and \frac{5}{3} to fractions with denominator 24.

$$\frac{235}{24}-\frac{40}{24}$$

Since \frac{235}{24} and \frac{40}{24} have the same denominator, subtract them by subtracting their numerators.

$$\frac{235-40}{24}$$

Subtract 40 from 235 to get 195.

$$\frac{195}{24}$$

Reduce the fraction \frac{195}{24} to lowest terms by extracting and canceling out 3.

$$\frac{65}{8}$$

Factor

$$\frac{5 \cdot 13}{2 ^ {3}} = 8\frac{1}{8} = 8.125$$