Solve 41/4+21/3=

$$4 \frac{ 1 }{ 4 } +2 \frac{ 1 }{ 3 } =$$

Evaluate

$$\frac{79}{12}\approx 6.583333333$$

Solution Steps

Multiply 4 and 4 to get 16.

$$\frac{16+1}{4}+\frac{2\times 3+1}{3}$$

Add 16 and 1 to get 17.

$$\frac{17}{4}+\frac{2\times 3+1}{3}$$

Multiply 2 and 3 to get 6.

$$\frac{17}{4}+\frac{6+1}{3}$$

Add 6 and 1 to get 7.

$$\frac{17}{4}+\frac{7}{3}$$

Least common multiple of 4 and 3 is 12. Convert \frac{17}{4} and \frac{7}{3} to fractions with denominator 12.

$$\frac{51}{12}+\frac{28}{12}$$

Since \frac{51}{12} and \frac{28}{12} have the same denominator, add them by adding their numerators.

$$\frac{51+28}{12}$$

Add 51 and 28 to get 79.

$$\frac{79}{12}$$

Factor

$$\frac{79}{2 ^ {2} \cdot 3} = 6\frac{7}{12} = 6.583333333333333$$