Solve 45/6-41/3=

$$4 \frac { 5 } { 6 } - 4 \frac { 1 } { 3 } =$$

Evaluate

$$\frac{1}{2}=0.5$$

Solution Steps

Multiply 4 and 6 to get 24.

$$\frac{24+5}{6}-\frac{4\times 3+1}{3}$$

Add 24 and 5 to get 29.

$$\frac{29}{6}-\frac{4\times 3+1}{3}$$

Multiply 4 and 3 to get 12.

$$\frac{29}{6}-\frac{12+1}{3}$$

Add 12 and 1 to get 13.

$$\frac{29}{6}-\frac{13}{3}$$

Least common multiple of 6 and 3 is 6. Convert \frac{29}{6} and \frac{13}{3} to fractions with denominator 6.

$$\frac{29}{6}-\frac{26}{6}$$

Since \frac{29}{6} and \frac{26}{6} have the same denominator, subtract them by subtracting their numerators.

$$\frac{29-26}{6}$$

Subtract 26 from 29 to get 3.

$$\frac{3}{6}$$

Reduce the fraction \frac{3}{6} to lowest terms by extracting and canceling out 3.

$$\frac{1}{2}$$

Factor

$$\frac{1}{2} = 0.5$$