Solve 43/5+71/2=

$$4 \frac { 3 } { 5 } + 7 \frac { 1 } { 2 } =$$

Evaluate

$$\frac{121}{10}=12.1$$

Solution Steps

Multiply 4 and 5 to get 20.

$$\frac{20+3}{5}+\frac{7\times 2+1}{2}$$

Add 20 and 3 to get 23.

$$\frac{23}{5}+\frac{7\times 2+1}{2}$$

Multiply 7 and 2 to get 14.

$$\frac{23}{5}+\frac{14+1}{2}$$

Add 14 and 1 to get 15.

$$\frac{23}{5}+\frac{15}{2}$$

Least common multiple of 5 and 2 is 10. Convert \frac{23}{5} and \frac{15}{2} to fractions with denominator 10.

$$\frac{46}{10}+\frac{75}{10}$$

Since \frac{46}{10} and \frac{75}{10} have the same denominator, add them by adding their numerators.

$$\frac{46+75}{10}$$

Add 46 and 75 to get 121.

$$\frac{121}{10}$$

Factor

$$\frac{11 ^ {2}}{2 \cdot 5} = 12\frac{1}{10} = 12.1$$