Solve 43/4+55/12=

$$4 \frac { 3 } { 4 } + 5 \frac { 5 } { 12 } =$$

Evaluate

$$\frac{61}{6}\approx 10.166666667$$

Solution Steps

Multiply 4 and 4 to get 16.

$$\frac{16+3}{4}+\frac{5\times 12+5}{12}$$

Add 16 and 3 to get 19.

$$\frac{19}{4}+\frac{5\times 12+5}{12}$$

Multiply 5 and 12 to get 60.

$$\frac{19}{4}+\frac{60+5}{12}$$

Add 60 and 5 to get 65.

$$\frac{19}{4}+\frac{65}{12}$$

Least common multiple of 4 and 12 is 12. Convert \frac{19}{4} and \frac{65}{12} to fractions with denominator 12.

$$\frac{57}{12}+\frac{65}{12}$$

Since \frac{57}{12} and \frac{65}{12} have the same denominator, add them by adding their numerators.

$$\frac{57+65}{12}$$

Add 57 and 65 to get 122.

$$\frac{122}{12}$$

Reduce the fraction \frac{122}{12} to lowest terms by extracting and canceling out 2.

$$\frac{61}{6}$$

Factor

$$\frac{61}{2 \cdot 3} = 10\frac{1}{6} = 10.166666666666666$$