Solve 414/45-17/15

$$4 \frac { 14 } { 45 } - 1 \frac { 7 } { 15 }$$

Evaluate

$$\frac{128}{45}\approx 2.844444444$$

Solution Steps

Multiply 4 and 45 to get 180.

$$\frac{180+14}{45}-\frac{1\times 15+7}{15}$$

Add 180 and 14 to get 194.

$$\frac{194}{45}-\frac{1\times 15+7}{15}$$

Multiply 1 and 15 to get 15.

$$\frac{194}{45}-\frac{15+7}{15}$$

Add 15 and 7 to get 22.

$$\frac{194}{45}-\frac{22}{15}$$

Least common multiple of 45 and 15 is 45. Convert \frac{194}{45} and \frac{22}{15} to fractions with denominator 45.

$$\frac{194}{45}-\frac{66}{45}$$

Since \frac{194}{45} and \frac{66}{45} have the same denominator, subtract them by subtracting their numerators.

$$\frac{194-66}{45}$$

Subtract 66 from 194 to get 128.

$$\frac{128}{45}$$

Factor

$$\frac{2 ^ {7}}{3 ^ {2} \cdot 5} = 2\frac{38}{45} = 2.8444444444444446$$