Solve 41/6-52/3+21/4

$$4 \frac { 1 } { 6 } - 5 \frac { 2 } { 3 } + 2 \frac { 1 } { 4 }$$

Evaluate

$$\frac{3}{4}=0.75$$

Solution Steps

Multiply 4 and 6 to get 24.

$$\frac{24+1}{6}-\frac{5\times 3+2}{3}+\frac{2\times 4+1}{4}$$

Add 24 and 1 to get 25.

$$\frac{25}{6}-\frac{5\times 3+2}{3}+\frac{2\times 4+1}{4}$$

Multiply 5 and 3 to get 15.

$$\frac{25}{6}-\frac{15+2}{3}+\frac{2\times 4+1}{4}$$

Add 15 and 2 to get 17.

$$\frac{25}{6}-\frac{17}{3}+\frac{2\times 4+1}{4}$$

Least common multiple of 6 and 3 is 6. Convert \frac{25}{6} and \frac{17}{3} to fractions with denominator 6.

$$\frac{25}{6}-\frac{34}{6}+\frac{2\times 4+1}{4}$$

Since \frac{25}{6} and \frac{34}{6} have the same denominator, subtract them by subtracting their numerators.

$$\frac{25-34}{6}+\frac{2\times 4+1}{4}$$

Subtract 34 from 25 to get -9.

$$\frac{-9}{6}+\frac{2\times 4+1}{4}$$

Reduce the fraction \frac{-9}{6} to lowest terms by extracting and canceling out 3.

$$-\frac{3}{2}+\frac{2\times 4+1}{4}$$

Multiply 2 and 4 to get 8.

$$-\frac{3}{2}+\frac{8+1}{4}$$

Add 8 and 1 to get 9.

$$-\frac{3}{2}+\frac{9}{4}$$

Least common multiple of 2 and 4 is 4. Convert -\frac{3}{2} and \frac{9}{4} to fractions with denominator 4.

$$-\frac{6}{4}+\frac{9}{4}$$

Since -\frac{6}{4} and \frac{9}{4} have the same denominator, add them by adding their numerators.

$$\frac{-6+9}{4}$$

Add -6 and 9 to get 3.

$$\frac{3}{4}$$

Factor

$$\frac{3}{2 ^ {2}} = 0.75$$