Solve 41/3-2+3-1/9=

$$4 \frac { 1 } { 3 } - 2 + 3 - \frac { 1 } { 9 } =$$

Evaluate

$$\frac{47}{9}\approx 5.222222222$$

Solution Steps

Multiply 4 and 3 to get 12.

$$\frac{12+1}{3}-2+3-\frac{1}{9}$$

Add 12 and 1 to get 13.

$$\frac{13}{3}-2+3-\frac{1}{9}$$

Convert 2 to fraction \frac{6}{3}.

$$\frac{13}{3}-\frac{6}{3}+3-\frac{1}{9}$$

Since \frac{13}{3} and \frac{6}{3} have the same denominator, subtract them by subtracting their numerators.

$$\frac{13-6}{3}+3-\frac{1}{9}$$

Subtract 6 from 13 to get 7.

$$\frac{7}{3}+3-\frac{1}{9}$$

Convert 3 to fraction \frac{9}{3}.

$$\frac{7}{3}+\frac{9}{3}-\frac{1}{9}$$

Since \frac{7}{3} and \frac{9}{3} have the same denominator, add them by adding their numerators.

$$\frac{7+9}{3}-\frac{1}{9}$$

Add 7 and 9 to get 16.

$$\frac{16}{3}-\frac{1}{9}$$

Least common multiple of 3 and 9 is 9. Convert \frac{16}{3} and \frac{1}{9} to fractions with denominator 9.

$$\frac{48}{9}-\frac{1}{9}$$

Since \frac{48}{9} and \frac{1}{9} have the same denominator, subtract them by subtracting their numerators.

$$\frac{48-1}{9}$$

Subtract 1 from 48 to get 47.

$$\frac{47}{9}$$

Factor

$$\frac{47}{3 ^ {2}} = 5\frac{2}{9} = 5.222222222222222$$