Solve 41/3-(3/2)^3=

$$4 \frac { 1 } { 3 } - ( \frac { 3 } { 2 } ) ^ { 3 } =$$

Evaluate

$$\frac{23}{24}\approx 0.958333333$$

Solution Steps

Multiply 4 and 3 to get 12.

$$\frac{12+1}{3}-\left(\frac{3}{2}\right)^{3}$$

Add 12 and 1 to get 13.

$$\frac{13}{3}-\left(\frac{3}{2}\right)^{3}$$

Calculate \frac{3}{2} to the power of 3 and get \frac{27}{8}.

$$\frac{13}{3}-\frac{27}{8}$$

Least common multiple of 3 and 8 is 24. Convert \frac{13}{3} and \frac{27}{8} to fractions with denominator 24.

$$\frac{104}{24}-\frac{81}{24}$$

Since \frac{104}{24} and \frac{81}{24} have the same denominator, subtract them by subtracting their numerators.

$$\frac{104-81}{24}$$

Subtract 81 from 104 to get 23.

$$\frac{23}{24}$$

Factor

$$\frac{23}{2 ^ {3} \cdot 3} = 0.9583333333333334$$