Solve 41/3+(-33/4)

$$4 \frac { 1 } { 3 } + ( - 3 \frac { 3 } { 4 } )$$

Evaluate

$$\frac{7}{12}\approx 0.583333333$$

Solution Steps

Multiply 4 and 3 to get 12.

$$\frac{12+1}{3}-\frac{3\times 4+3}{4}$$

Add 12 and 1 to get 13.

$$\frac{13}{3}-\frac{3\times 4+3}{4}$$

Multiply 3 and 4 to get 12.

$$\frac{13}{3}-\frac{12+3}{4}$$

Add 12 and 3 to get 15.

$$\frac{13}{3}-\frac{15}{4}$$

Least common multiple of 3 and 4 is 12. Convert \frac{13}{3} and \frac{15}{4} to fractions with denominator 12.

$$\frac{52}{12}-\frac{45}{12}$$

Since \frac{52}{12} and \frac{45}{12} have the same denominator, subtract them by subtracting their numerators.

$$\frac{52-45}{12}$$

Subtract 45 from 52 to get 7.

$$\frac{7}{12}$$

Factor

$$\frac{7}{2 ^ {2} \cdot 3} = 0.5833333333333334$$