Solve 4div|-4|-(-1/3)^2+(pi-2)^0-(-1)^2010

$$4 \div | - 4 | - ( - \frac { 1 } { 3 } ) ^ { 2 } + ( \pi - 2 ) ^ { 0 } - ( - 1 ) ^ { 2010 }$$

Evaluate

$$\frac{8}{9}\approx 0.888888889$$

Solution Steps

The absolute value of a real number a is a when a\geq 0, or -a when a<0. The absolute value of -4 is 4.

$$\frac{4}{4}-\left(-\frac{1}{3}\right)^{2}+\left(\pi -2\right)^{0}-\left(-1\right)^{2010}$$

Divide 4 by 4 to get 1.

$$1-\left(-\frac{1}{3}\right)^{2}+\left(\pi -2\right)^{0}-\left(-1\right)^{2010}$$

Calculate -\frac{1}{3} to the power of 2 and get \frac{1}{9}.

$$1-\frac{1}{9}+\left(\pi -2\right)^{0}-\left(-1\right)^{2010}$$

Subtract \frac{1}{9} from 1 to get \frac{8}{9}.

$$\frac{8}{9}+\left(\pi -2\right)^{0}-\left(-1\right)^{2010}$$

Calculate \pi -2 to the power of 0 and get 1.

$$\frac{8}{9}+1-\left(-1\right)^{2010}$$

Add \frac{8}{9} and 1 to get \frac{17}{9}.

$$\frac{17}{9}-\left(-1\right)^{2010}$$

Calculate -1 to the power of 2010 and get 1.

$$\frac{17}{9}-1$$

Subtract 1 from \frac{17}{9} to get \frac{8}{9}.

$$\frac{8}{9}$$

Factor

$$\frac{2 ^ {3}}{3 ^ {2}} = 0.8888888888888888$$