Solve 4*9(t_{1}-3)^2

$$4 \cdot 9 ( t _ { 1 } - 3 ) ^ { 2 }$$

Evaluate

$$36\left(t_{1}-3\right)^{2}$$

Solution Steps

Multiply 4 and 9 to get 36.

$$36\left(t_{1}-3\right)^{2}$$

Use binomial theorem \left(a-b\right)^{2}=a^{2}-2ab+b^{2} to expand \left(t_{1}-3\right)^{2}.

$$36\left(t_{1}^{2}-6t_{1}+9\right)$$

Use the distributive property to multiply 36 by t_{1}^{2}-6t_{1}+9.

$$36t_{1}^{2}-216t_{1}+324$$

Expand

$$36t_{1}^{2}-216t_{1}+324$$

Solution Steps

Multiply 4 and 9 to get 36.

$$36\left(t_{1}-3\right)^{2}$$

Use binomial theorem \left(a-b\right)^{2}=a^{2}-2ab+b^{2} to expand \left(t_{1}-3\right)^{2}.

$$36\left(t_{1}^{2}-6t_{1}+9\right)$$

Use the distributive property to multiply 36 by t_{1}^{2}-6t_{1}+9.

$$36t_{1}^{2}-216t_{1}+324$$