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4^{a}=2
Use the rules of exponents and logarithms to solve the equation.
\log(4^{a})=\log(2)
Take the logarithm of both sides of the equation.
a\log(4)=\log(2)
The logarithm of a number raised to a power is the power times the logarithm of the number.
a=\frac{\log(2)}{\log(4)}
Divide both sides by \log(4).
a=\log_{4}\left(2\right)
By the change-of-base formula \frac{\log(a)}{\log(b)}=\log_{b}\left(a\right).