Solve for a
a=0
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4^{2a}=1
Use the rules of exponents and logarithms to solve the equation.
\log(4^{2a})=\log(1)
Take the logarithm of both sides of the equation.
2a\log(4)=\log(1)
The logarithm of a number raised to a power is the power times the logarithm of the number.
2a=\frac{\log(1)}{\log(4)}
Divide both sides by \log(4).
2a=\log_{4}\left(1\right)
By the change-of-base formula \frac{\log(a)}{\log(b)}=\log_{b}\left(a\right).
a=\frac{0}{2}
Divide both sides by 2.
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