Solve 4^2+(3+49)*2:7

$$4 ^ { 2 } + ( 3 + 49 ) \cdot 2 : 7$$

Evaluate

$$\frac{216}{7}\approx 30.857142857$$

Solution Steps

Calculate 4 to the power of 2 and get 16.

$$16+\frac{\left(3+49\right)\times 2}{7}$$

Add 3 and 49 to get 52.

$$16+\frac{52\times 2}{7}$$

Multiply 52 and 2 to get 104.

$$16+\frac{104}{7}$$

Convert 16 to fraction \frac{112}{7}.

$$\frac{112}{7}+\frac{104}{7}$$

Since \frac{112}{7} and \frac{104}{7} have the same denominator, add them by adding their numerators.

$$\frac{112+104}{7}$$

Add 112 and 104 to get 216.

$$\frac{216}{7}$$

Factor

$$\frac{2 ^ {3} \cdot 3 ^ {3}}{7} = 30\frac{6}{7} = 30.857142857142858$$